How want to have application based on Spring Boot, maven and OSGI framework. The application should run as standalone without need to deploy to some osgi container like Apache Karaf (can be inluded e.g. in JAR/WAR file). Can you give me all settings a based project structure for that ?
Certainly! Here is an example project structure for a Spring Boot application using Maven andGi:
├── pom.xml ├── src │ ├── main │ │ ├── java │ │ │ ├── com │ │ │ │ ├── mycompany │ │ │ │ ├── myapp │ │ │ │ │ │ ├── Application.java │ │ │ │ │ │ └── ... │ │ │ │ └── ... │ │ ├── resources │ │ │ ├── application.properties │ │ │ └── ... │ └── test │ ├── java │ │ ├── com │ │ │ ├── mycompany │ │ │ │ ├── myapp │ │ │ │ │ ├── ApplicationTests.java │ │ │ │ └── ... │ │ │ └── ... │ │ ├── resources │ │ └── ... │ └── pom.xml ├── README.md └── ...
The pom.xml
file should include the necessary dependencies for Spring Boot, OSGi, and the contained bundles. Here's an example pom.xml
file for a basic OSGi-enabled Spring Boot application:
<?xml version="1.0" encoding="UTF-8"?> <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>com.mycompany</groupId> <artifactId>myapp</artifactId> <version>1.0-SNAPSHOT</version> <parent> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-parent</artifactId> <version>2.6.2</version> </parent> <properties> <java.version>1.8</java.version> <osgi.version>1.0.0</osgi.version> <osgi-framework.version>1.0.0</osgi-framework.version> </properties> <dependencies> <!-- Spring Boot --> dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-web</artifactId> </dependency> <!-- OSGi --> <dependency> groupId>org.osgi</groupId> <artifactId>osgi-framework</artifactId> <version>osgi.version}</version> </dependency> <dependency> <groupId>org.osgi</groupId> <artifactId>osgi-core</artifactId> <version>${osgi.version}</version> </dependency> <!-- Spring Framework --> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-context</artifactId> </dependency> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-web</artifactId <version>5.3.13</version> </dependency> <!-- Web --> <dependency> <groupId>org.apache.commons</groupId> <artifactId>commons-lang3</artifactId> <version>3.12.0</version> </dependency> <!-- Test --> <dependency> <groupId>org.junit.jupiter</groupId> <artifactId>junit-jupiter</artifactId> <version>5.8.2</version> <scope>test</scope> </dependency> </dependencies> <build> <plugins> <plugin> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-maven-plugin</artifactId> </> </plugins> </build>
Can you give me example of interface and 2 implementation. One of that will be in the runtime and the second will be added as a new module after start of application. Show me also how I can register new module. I expected that module will be packed into jar file.
Sure, here's an example:
package com.mycompany.my.module; public interface MyModule { void doSomething(); }
package com.mycompany.myapp.module.impl1; import com.mycompany.myapp.module.MyModule; public class ModuleImpl1 implements MyModule { @Override public void doSomething() { // implementation 1 } }
package com.mycompany.myapp.module.impl2; import com.mycompany.myapp.module.MyModule; public class ModuleImpl2 implements MyModule { @Override public void doSomething() { // implementation 2 } }
Assuming you have a jar file containing the implementation classes, you can add it to the Spring Boot application using the Maven
or Gradle
build tool. Here's an example of how to add the jar file to the project using Maven
:
<dependencies> <dependency> <groupId>com.mycompany</groupId> <artifactId>myapp-module</artifactId> <version>1.0.0</version> </dependency> </dependencies>
Once the jar file is added to the project, you can register the new module in the application.properties
file:
spring.application.modules=com.mycompany.myapp.module.impl1,com.mycompany.myapp.module.impl2
This will register both the implementation 1 and implementation 2 classes as modules in the Spring Boot application.
To register the new module in the runtime, you can use the OsgiContext
interface and the OsgiFramework
class provided by the org.springframework.osgi
package. Here's an example of how to register the new module in the runtime:
@Configuration public class MyAppConfig { @Bean public OsgiContextFactory osgiContextFactory() { return OsgiContextFactory.createDefaultContextFactory(); } @Bean public OsgiFramework osgiFramework() { return OsgiFrameworkBuilder.create() .withContextFactory(osgiContextFactory()) .build(); } @Bean public MyModule myModule() { return new ModuleImpl1(); } }
This configuration will register the ModuleImpl1
class as a module in the OSGi runtime. You can also register other modules in the runtime by adding corresponding @Bean
definitions in the configuration class.
Note that the MyModule
interface and the ModuleImpl1
and ModuleImpl2
classes should be packaged in a jar file and added to the project using the Maven or Gradle build tool.
How I can add the new module, when the program is already running ? Can I added bean dynamically ?
Yes, it is possible to add a new module to an already running Spring Boot application using OSGi. As long as the new module is packaged as an OSGi bundle and provides the necessary OSGi headers, it can be added to the application at runtime.
To add a new module, you can use the Activator
interface provided by the org.osgi.framework
package. The Activator
interface allows you to register the new module with the OSGi runtime.
Here is an example Activator
class that you can use to add a new module:
package com.mycompany.myapp.module.activator; import org.osgi.framework.BundleActivator; import org.osgi.framework.BundleContext; public class ModuleActivator implements BundleActivator { @Override public void start(BundleContext context) throws Exception { // Register the new module with the OSGi runtime context.registerService("com.mycompany.myapp.module", new ModuleImpl1(), null); } @Override public void stop(BundleContext context) throws Exception { // Unregister the new module from OSGi runtime context.unregisterService("com.mycompany.myapp.module", new ModuleImpl1(), null); } }
This Activator
class will register the ModuleImpl1
class as a new module with the OSGi runtime when the start
method is called. When the stop
method is called, the module will be unregistered from the OSGi runtime.
To register the Activator
class with the OSGi runtime, you can use the OsgiContext
interface and the OsgiFramework
class provided by the org.springframework.osgi
package. Here is an example of how you can register the Activator
class:
@Configuration public class MyAppConfig { @Bean public OsgiContextFactory osgiContextFactory() { return OsgiContextFactory.createDefaultContextFactory(); } @Bean public OsgiFramework osgiFramework() { return OsgiFrameworkBuilder.create() .withContextFactory(osgiContextFactory()) .build(); } @Bean public BundleActivator bundleActivator() { return new ModuleActivator(); } @Bean public MyModule myModule() { return new ModuleImpl1(); } }
This configuration will register the ModuleActivator
class as a BundleActivator
with the OSGi runtime, allowing you to register and unregister the ModuleImpl1
class as a new module at runtime.
How to upload jar file contains new module implementation to the application, read the content and based on that active new module.
To upload a jar file that contains the implementation of a new module to a running Spring Boot application, you can use the OSGi subsystem.
Here are the steps to follow:
OsgiBundle
interface provided by the org.osgi.framework
package to create a new OsgiBundle
object that represents the new jar file.OsgiBundleContext
interface provided by the org.osgi.framework
package to create a new OsgiBundleContext
object that represents the OSGi bundle context of the running application.OsgiBundle
object to load the new jar file into the OSGi bundle context of the running application.Bundle
interface provided by the org.osgi.framework
package to access the new module implementation.Here is an example of how you can upload a jar file that contains the implementation of a new module to a running Spring Boot application:
@Configuration public class MyAppConfig { @Bean public OsgiContextFactory osgiContextFactory() { return OsContextFactory.createDefaultContextFactory(); } @Bean public OsgiFramework osgiFramework() { return OsgiFrameworkBuilder.create() .withContextFactory(osgiContextFactory()) .build(); } @Bean public MyModule myModule() { // Read the contents of the new jar file String jarFilePath = "path/to/new/jar/file.jar"; try { InputStream is = new FileInputStream(jarFilePath); JarInputStream jis = new JarInputStream(is); JarEntry entry; while((entry = jis.getNextEntry()) != null) { String entryName = entry.getName(); if (entryName.endsWith(".class")) { // Read the class file and extract the new module implementation Class<?> clazz = Class.forName(entryName); if (clazz != null && MyModule.class.isAssignableFrom(clazz)) { // Create a new instance of the new module implementation and return it return (MyModule) clazz.newInstance(); } } } } catch (Exception e) { e.printStackTrace(); } return null; } }
This configuration will read the contents of the new jar file and extract the new module implementation. Once the new module implementation is extracted, it will be registered as a bean in the Spring Boot application, and it will be available for use.
I want to have loading new modules as service
Sure, here's an example of how you can use the OsgiBundle
interface provided by the org.osgi.framework
package to load a new module as a service in a Spring Boot application:
@Configuration public class MyAppConfig { @Bean public OsgiContextFactory osgiContext() { return OsContextFactory.createDefaultContextFactory(); } @Bean public OsgiFramework osgiFramework() { return OsgiFrameworkBuilder.create() .withContextFactory(osgiContextFactory()) .build(); } @Bean public MyModule myModule() { return new MyModule(); } } public class MyModule implements ServiceFactory<MyService> { @Override public MyService createService(BundleContext context) { // Create a new instance of MyService return new MyService(); } @Override public void ungetService(BundleContext context, MyService service) { // Destroy the MyService instance } } public interface MyService { // Define the methods of MyService } public class MyServiceImpl implements MyService { // Implement the methods of MyService }
In this example, the MyModule
class implements the ServiceFactory
interface provided by the org.osgi.framework
package The ServiceFactory
interface allows you to create a new instance of a service and return it to the caller. The MyModule
class creates a new instance of MyServiceImpl
and returns it to the caller.
Once the MyModule
class is registered as a service in the OSGi runtime, you can use the OsgiBundle
interface provided by the org.osgi.framework
package to load the new module as a service. Here's an example of how you can do this:
OsgiBundle bundle = osgiFramework.getBundleContext().getBundle(MyModule.class); MyService myService = (MyService) bundle.getService(MyService.class);
This code will load the MyModule
class as a service in the OSGi runtime, and it will create a new instance of MyServiceImpl
and return it to the caller.
Note that you will need to import the org.osgi.framework
package in order to use the OsgiBundle
interface and the ServiceFactory
interface. You can do this by adding the following import statement to your code:
import org.osgi.framework.OsgiBundle; import org.osgi.framework.ServiceFactory;